If sectheta=m, tantheta = n, then 1/m[(m...

If `sectheta=m, tantheta = n`, then `1/m[(m+n)+1/(m+n)]`....................... A) 2 B) 2m C) 2n D) mn

A

2

B

2m

C

2n

D

mn

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The correct Answer is:

A

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