If "cosec " theta - sin theta = m, sec ...

If ` "cosec " theta - sin theta = m, sec theta - cos theta =n , " then "(m^(2)n)^(2//3) + (mn^(2))^(2//3)`=.................. A) 1 B) 2 C) 1/2 D) 0

A

1

B

2

C

`1/2`

D

0

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The correct Answer is:

A

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