If cos (theta -alpha) =a, sin (theta - b...

If `cos (theta -alpha) =a, sin (theta - beta) =b, ` then `cos ^(2) (alpha - beta) + 2 ab sin (alpha - beta) ` is equal to

A

`4a ^(2) b ^(2)`

B

`a^(2) -b^(2)`

C

`a ^(2) +b^(2)`

D

`-a^(2) b^(2)`

Verified by Experts

The correct Answer is:

C

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