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If sin 2 theta + sin 2 phi =1/2 and cos ...

If `sin 2 theta + sin 2 phi =1/2 and cos 2 theta + cos 2 phi =3/2,` then `cos ^(2) (theta - phi)=`

A

`sqrt((a^(2) +b^(2))/(4-a^(2) -b^(2)))`

B

`sqrt((4- a^(2) -b^(2))/(a^(2) +b^(2)))`

C

`sqrt((a^(2) +b^(2))/(4+a^(2) +b^(2)))`

D

`sqrt((4+ a^(2)+b^(2))/(a^(2) +b^(2)))`

Text Solution

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The correct Answer is:
B
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