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Let fn(Theta)=(tan(Theta/2))(1 +sec(Thet...

Let` f_n(Theta)=(tan(Theta/2))(1 +sec(Theta))(1+sec(2Theta)).....(1+sec(2^nTheta)`.. then

A

`f_(2) ((pi)/(16))=1`

B

`f_(3) ((pi)/(32)) =1`

C

`f_(4) ((pi)/(64)) =1`

D

`f_(5) ((pi)/(128))=1`

Text Solution

Verified by Experts

The correct Answer is:
D
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