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If A+B+C = 180^@ then (sin 2A + sin 2B +...

If `A+B+C = 180^@` then `(sin 2A + sin 2B + sin 2C) / (cosA + cosB + cosC - 1) =`

A

`8 sin ""A/2 sin ""B/2 sin ""C/2`

B

`8 cos ""A/2 cos ""B/2 cos ""C/2`

C

`8 sin ""A/2 cos ""B/2 cos ""C/2`

D

`8 cos ""A/2 sin ""B/2 sin ""C/2`

Text Solution

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The correct Answer is:
B
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