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If A=[(2,-3,3),(2,2,3),(3,-2,2)] then ...

If `A=[(2,-3,3),(2,2,3),(3,-2,2)] ` then
`C_(2)+2C_(1) and "then" R_(1)+R_(3)` gives

A

`[(2,1,3),(2,6,3),(3,4,2)] `

B

`[(2,-1,3),(2,4,3),(3,1,2)] `

C

`[(5,5,5),(3,4,3),(2,6,3)] `

D

`[(5,5,5),(2,6,3),(3,4,2)] `

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The correct Answer is:
D
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