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If A={:[(3,2),(0,1)]:}" then:(A^(-1))^(3...

If `A={:[(3,2),(0,1)]:}" then:(A^(-1))^(3)=`...a)`(1)/(27)[(1,-26),(0,27)]` b)`(1)/(27)[(-1,26),(0,27)]`c)`(1)/(27)[(1,-26),(0,-27)]` d)`(1)/(27)[(-1,-26),(0,-27)]`

A

`(1)/(27)[(1,-26),(0,27)]`

B

`(1)/(27)[(-1,26),(0,27)]`

C

`(1)/(27)[(1,-26),(0,-27)]`

D

`(1)/(27)[(-1,-26),(0,-27)]`

Text Solution

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The correct Answer is:
a
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