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If bara,barb,barc are non-coplanar vecto...

If `bara,barb,barc` are non-coplanar vectors then `[bar(a)+2bar(b)" "bar(a)+bar(c)" "bar(b)]=`

A

0

B

`[bara,barb,barc]`

C

`-[bara,barb,barc]`

D

`2[bara,barb,barc]`

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The correct Answer is:
C
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