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[bar(a)" "bar(b)" "bar(a)xxbarb] is equa...

`[bar(a)" "bar(b)" "bar(a)xxbarb]` is equal to

A

`|baraxxbarb|`

B

`|baraxxbarb|^2`

C

0

D

None of these

Text Solution

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The correct Answer is:
B
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