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For any three vectors bara,barb and barc...

For any three vectors `bara,barb and barc,(bara-barb) .[(barb+barc)xx(barc+bara)]` is equal to:

A

(a) `2bara.(barbxxbarc)`

B

(b) `[bara" "barb" "barc]`

C

(c) `[bara" "barb" "barc]^2`

D

(d) 0

Text Solution

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The correct Answer is:
D
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