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If bara,barb and barc are three non-copl...

If `bara,barb` and `barc` are three non-coplanar vectors, then : `(bara + barb + barc) · [(bara + barb) xx (bara + barc)]` =

A

(a) `0`

B

(b) `[bara" "barb" "barc]`

C

(c) `-[bar(a)bar(b)bar(c)]`

D

(d) `2[bara,barb,barc]`

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The correct Answer is:
C
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