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If bar r=l(bar b xx bar c)+m(bar c xx b...

If `bar r=l(bar b xx bar c)+m(bar c xx bar a)+n(bar a xx bar b) and [bar a bar b bar c]=2`,
then `l+m+n` is equal to

A

(a) `(bara+barb+barc)barr`

B

(b) `1/2(bara+barb+barc)barr`

C

(c) `1/3(bara+barb+barc)(bara+barb+barc)`

D

(d) `2/3(bara+barb+barc)barr`

Text Solution

Verified by Experts

The correct Answer is:
B
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