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The value of (bara-barb).[(barb-barc)xx(...

The value of `(bara-barb).[(barb-barc)xx(barc-bara)]` is

A

0

B

`2[bara" "barb" "barc]`

C

`3[bara" "barb" "barc]`

D

None of these

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The correct Answer is:
A
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