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If barx.bara=0,barx.barb=0 and barx.barc...

If `barx.bara=0,barx.barb=0 and barx.barc=0` for some non-zero vector x, then the TRUE statement is: a)`[bara" "barb" "barc]=0` b)`[bara" "barb" "barc] ne0` c)`[bara" "barb" "barc] =1` d)None of these

A

`[bara" "barb" "barc]=0`

B

`[bara" "barb" "barc] ne0`

C

`[bara" "barb" "barc] =1`

D

None of these

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The correct Answer is:
A
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