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If vecu, vecv, vecw are non -coplanar v...

If `vecu, vecv, vecw` are non -coplanar vectors and `p,q,` are real numbers then the equality
`[3vecu p vecv p vecw]-[p vecv vecw qvecu]-[2vecw-qvecv qvecu]=0` holds for

A

exactly one value of `(p.q)`

B

exactly two value of `(p.q)`

C

more than two but not all values of `(p.q)`

D

all values of `(p,q)`

Text Solution

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The correct Answer is:
A
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