Home
Class 12
MATHS
In a right angled triangle ABC, the hypo...

In a right angled triangle ABC, the hypotenuse AB =p,
then `vec(AB).vec(AC) + vec(BC).vec(BA)+vec(CA).vec(CB)` is equal to:

A

(a) `3p^2`

B

(b) `(3p^2)/(2)`

C

(c) `p^2`

D

(d) `p^2/2`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

When vec(A)*vec(B)=-|vec(A)||vec(B)|, then

If vec(A)xxvec(B)=vec(B)xxvec(A) , then the angle between vec(A) and vec(B) is-

The area of a triangle formed by the sides of vector vec(A)and vec(B) is

Assertion : vec(A)xxvec(B) is perpendicular to both vec(A)+vec(B) as well as vec(A)-vec(B) . Reason: vec(A)+vec(B) as well as vec(A)-vec(B) lie in the plane contanining vec(A)and vec(B) , but vec(A)xxvec(B) lies perpendicular to the plane containing A and B.

If |vec(A)+vec(B)|=|vec(A)|+|vec(B)|, then angle between vec(A)and vec(B) will be

Under what condition |vec(A)+vec(B)| = |vec(A)|+|vec(B)| holds good?