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If bara.barb=barb.barc=barc.bara=0 and b...

If `bara.barb=barb.barc=barc.bara=0` and `bara, barb, barc` are non-zero, then the value of `[bara" "barb" "barc]` is equal to: a)`1` b)`-1` c)`0` d)`|bara||barb||barc|`

A

1

B

`-1`

C

`|bara||barb||barc|`

D

0

Text Solution

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The correct Answer is:
C
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