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The equation of tangent to the curve y=2...

The equation of tangent to the curve `y=2 sinx` at `x=pi/4` is:
a)`y-sqrt2=2sqrt2(x-pi/4)`
b)`y+sqrt2=sqrt2(x+pi/4)`
c)`y-sqrt2=-sqrt2(x-pi/4)`
d)`y-sqrt2=sqrt2(x-pi/4)`

A

`y-sqrt2=2sqrt2(x-pi/4)`

B

`y+sqrt2=sqrt2(x+pi/4)`

C

`y-sqrt2=-sqrt2(x-pi/4)`

D

`y-sqrt2=sqrt2(x-pi/4)`

Text Solution

Verified by Experts

The correct Answer is:
D
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