Home
Class 12
MATHS
The equation of the tangent to the curve...

The equation of the tangent to the curve `y=4+cos^2x` at `x=pi/2` is

A

(a) `y=4`

B

(b) `y+4=0`

C

(c) `y=0`

D

(d) `y+2=0`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the tangent to the curve y=2 sin x +sin 2x at x=pi/3 is equal to: a) 2y=3sqrt3 b) y=3sqrt3 c) 2y+3sqrt3=0 d) y+3sqrt3=0

Find the equation of the tangent to the curve y=x-sinxcosx at x=pi/2

The equation of tangent to the curve y=2 sinx at x=pi/4 is: a) y-sqrt2=2sqrt2(x-pi/4) b) y+sqrt2=sqrt2(x+pi/4) c) y-sqrt2=-sqrt2(x-pi/4) d) y-sqrt2=sqrt2(x-pi/4)

The equation of the tangent to the curve y=x+4/(x^(2)), that is parallel to the X-axis, is

The equation of the tangent to the curve y=1-e^(x/2) at the point of intersection with Y-axis is A) x+2y=0 B) 2x+y=0 C) x-y=2 D) x+y=2

The equation of the tangent to the curve x=2cos^(3) theta and y=3sin^(3) theta at the point, theta =pi//4 is

The equation of normal to the curve y=2cosx at x=pi/4 is: a) y-sqrt2=2sqrt2(x-pi/4) b) y+sqrt2=2sqrt2(x+pi/4) c) y-sqrt2=1/sqrt2(x-pi/4) d) y-sqrt2=sqrt2(x-pi/4)