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Find the point on the parabola y=(x-3)...

Find the point on the parabola `y=(x-3)^2,` where the tangent is parallel to the line joining (3,0) and (4,1). a)`(5/2,1/4)` b)`(5/2,3/4)` c)`(7/2,1/4)` d)`(1/2,1/4)`

A

`(5/2,1/4)`

B

`(5/2,3/4)`

C

`(7/2,1/4)`

D

`(1/2,1/4)`

Text Solution

Verified by Experts

The correct Answer is:
C
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