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The fixed point P on the curve y=x^(2)-4...

The fixed point P on the curve `y=x^(2)-4x+5` such that the tangent at P is perpendicular to the line `x+2y-7=0` is given by: a)(1,2) b)(2,1) c)(3,2) d)(2,3)

A

(1,2)

B

(2,1)

C

(3,2)

D

(2,3)

Text Solution

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The correct Answer is:
C
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