The normal to the curve x^(2)+2xy-3y^(2)...

The normal to the curve `x^(2)+2xy-3y^(2)=0,` at `(1,1)`

A

(a) does not meet the curve again

B

(b) meets the curve again in the second quadrant

C

(c) meets the curve again in the third quadrant

D

(d) meets the curve again in the fourth quadrant

Verified by Experts

The correct Answer is:

D

Similar Questions

Explore conceptually related problems

The normal to the curve x^2 +2xy-3 y^2 = 0 at (1, 1)

Find the slope of the normal to the curve y=x^2-1/(x^2) at (-1, 0)

The distance between the origin and the normal to the curve y=e^(2x)+x^(2) at x=0 is

The equation of normal to the curve y=x^2-2x+1 at (0,1) is

The equation of normal to the curve x^(2//3)+y^(2//3)=a^(2//3) at (asin^(3) theta, a cos^(3) theta) is

The equation of the normal to the curve y="sin"(pix)/2 at (1,1) is: a) y=1 b) x=1 c) y=x d) y-1=(-2)/pi(x-1)

Find the equations of the normals to the curve 3x^2 - y^2= 8 , which are parallel to the line x+3y = 4

The equation of the normal to the curve y=(1+x)^y+sin^(-1)(sin^2x) at x=0 is :