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For the function f(x)=(x-1)(x-2) defined...

For the function `f(x)=(x-1)(x-2)` defined on `[0,1/2]`,
the value of 'c' satisfying Lagrange's mean value theorem is

A

(a) `1/3`

B

(b) `1/5`

C

(c) `1/7`

D

(d) `1/4`

Text Solution

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The correct Answer is:
D
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