The function `f(x)=2x^3-15 x^2+36 x+4` is maximum at `x=` (a) 3 (b) 0 (c) 4 (d) 2

A

0

B

3

C

4

D

2

Verified by Experts

The correct Answer is:

D

Similar Questions

Explore conceptually related problems

The function f(x)=2x^3-3x^2-12x+5 has a minimum at x=...a) -1 b) 2 c) -1/2 d) 3/2

The function f(x) = (x^(2)-4)/(sin x-2) is

The function f(x) = (4-x^(2))/(4x-x^(3)) is

The function x^(5)-5x^(4)+ 5x^(3) -10 has a maxima, when x= a)3 b)2 c)1 d)0

At x=-1, the function f(x) = 2 x^3 -3 x^2 -12x+12 is...... A) maximum B) minimum C) neither maximum or minimum D) increasing

The function f(x) = (|3x-4|)/(3x-4) is discontinuous at

For which interval the given function f(x)=2x^3-9x^2+12x+1 is decreasing? a) (-2,infty) b) (-2,1) c) (-infty,-1) d) (1,2)

If the function f(x)=x^3-12ax^2+36a^2x-4(agt0) attains its maximum and minimum at x=p and x=q respectively, and if 3p=q^2 , then a is equal to

The maximum value of function f(x)=x^3-12 x^2+36 x+17 in the interval [1,10] is a. 17 b. 177 c. 77 d. none of these

The function f(x)=2x^(3)-3x^(2)-12x-4 has: a)No maxima and minima b)One maxima and one minima c)Two maxima d)Two minima