int(1)^(2)(cos(logx))/xdx=...

`int_(1)^(2)(cos(logx))/xdx=`

A

`sin(log3)`

B

`sin(log2)`

C

`cos(log3)`

D

`cos(log2)`

Verified by Experts

The correct Answer is:

B

int(1)^(2)(cos(logx))/xdx=
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