int(0)^(pi//6)(2+3x^(2))cos3x dx= (a) 1...

`int_(0)^(pi//6)(2+3x^(2))cos3x dx=`
(a) `1/36(pi+16)`

A

(a) `1/36(pi+16)`

B

(b) `1/36(pi-16)`

C

(c) `1/36(pi^(2)-16)`

D

(d) `1/36(pi^(2)+16)`

Verified by Experts

The correct Answer is:

D

int(0)^(pi//6)(2+3x^(2))cos3x dx= (a) 1/36(pi+16)
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