If g(1)=g(2), then int(1)^(2)[f{g(x)}]^(...

If `g(1)=g(2),` then `int_(1)^(2)[f{g(x)}]^(-1)f'{g(x)}g'(x)dx` is equal to

A

(a) `1`

B

(b) `2`

C

(c) `0`

D

(d) None of these

Verified by Experts

The correct Answer is:

C

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