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int(0)^((pi)/2)(x-[cosx])dx= (where [t...

`int_(0)^((pi)/2)(x-[cosx])dx=`
(where `[t]=` greatest integer less or equal to `t`)

A

`(pi)/4`

B

`(pi^(2))/8-(pi)/8`

C

`(pi^(2))/8-1`

D

`(pi^(2))/8`

Text Solution

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The correct Answer is:
D
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