If for nonzero x ,af(x)+bf(1/x)=1/x-5, ...

If for nonzero `x ,af(x)+bf(1/x)=1/x-5,`
where `a!=b` then `int_1^2f(x)dx= _ `

A

(a) `1/((a^(2)+b^(2)))[a log 2 -5a7/2b]`

B

(b) `1/((a^(2)-b^(2)))[a log 2-5a+7/2b]`

C

(c) `1/((a^(2)-b^(2)))[a log -5a-7/2b]`

D

(d) `1/((a^(2)+b^(2)))[a log 2-5a-7/2b]`

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The correct Answer is:

B

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