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The solution of (1+x^2) "dy"/"dx"=1 is...

The solution of `(1+x^2) "dy"/"dx"=1` is

A

`y=log (1+x^2) +c `

B

`y+ log (1+x^2) =c `

C

`y=log (1+x) = c `

D

`y=tan^(-1) x +c `

Text Solution

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The correct Answer is:
D
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