The degree of the differential equation `3(d^2y)/(dx^2)= {1+("dy"/"dx")^2}^(3/2)` is

A

1

B

2

C

3

D

6

Verified by Experts

The correct Answer is:

B

Similar Questions

Explore conceptually related problems

The degree of the differential equation (d^2y)/(dx^2)+ sqrt(1+("dy"/"dx")^3)=0 is

The degree of the differential equation (d^2y)/(dx^2)-sqrt("dy"/"dx")-3=x is

Degree of the given differential equation ((d^2y)/(dx^2))^3 = (1+(dy)/(dx))^(1/2) is

The order and degree of the differential equation (d^2y)/(dx^2)={y+((dy)/(dx))^2}^(1/4) are respectively

The order and degree of the differential equation ((d^2y)/(dx^2))^(1/3)+(x+"dy"/"dx")^(1//2) =0 are

The differential equation x((d^2y)/(dx^2))^3 + ("dy"/"dx")^4 y = x^2 is of

Degree of the given differential equation ((d^2y)/(dx^2))^3=(1+(dy)/(dx))^(1/2) is

The degree of the differential equation (d^2y)/(dx^2)+sqrt(1+((dy)/(dx))^3) =0 is

The degree of the differential equation (d^2y)/(dx^2)-sqrt((dy)/(dx)-3)=x is

The order and degree of the differential equation (d^2y)/(dx^2)+("dy"/"dx")^(1/3)+x^(1/4)=0 are respectively