Home
Class 12
MATHS
The degree of the differential equation ...

The degree of the differential equation `[1+("dy"/"dx")^2]^2=(d^2y)/(dx^2)` is

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The degree of the differential equation [1+((dy)/(dx))^2]^(3//4)=((d^2y)/(dx^2))^(1//3) is

The order and degree of the differential equation p=[(1+("dy"/"dx")^2)/((d^2y)/(dx^2))]^(3/2) respectively are

Find the degree of the differential equation: [1+(dy/dx)^2]^(3/4)=((d^2y)/dx^2)^(1/3)

The order and degree of the differential equation [1+(dy/dx)^3]^(7/3=7 d^2y/dx^2 are respectively………….

The degree of the differential equation 3(d^2y)/(dx^2)={1+((dy)/(dx))^2}^(3/2) is

The order and degree of the differential equation sqrt(1+(dy/dx)^3)=(d^2y/dx^2)^(3/2) are respectively…………

The order of the differential equation ((d^3y)/(dx^3))^2 + ((d^2y)/(dx^2))^2 + ((dy)/(dx))^5 =0 is

The degree of the differential equation (d^2y)/(dx^2)+sqrt(1+((dy)/(dx))^3) =0 is

The degree of the differential equation (d^2y)/(dx^2)-sqrt((dy)/(dx)-3)=x is