The solution of the differential equatio...

The solution of the differential equation `2x^2y"dy"/"dx"=tan(x^2y^2) -2xy^2`,
where `y=sqrt(pi/2)` where x =1, is

A

(a) `sin (x^2y^2)=e^(x-1)`

B

(b) `sin(x^2y^2)=x`

C

(c) `cos (x^2y^2)+x =0`

D

(d) `sin (x^2y^2)=e.e^x`

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The correct Answer is:

A

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