Home
Class 11
PHYSICS
A force of 1.732 xx 10^(-2) N acts on a ...

A force of `1.732 xx 10^(-2)` N acts on a particleof charge q moving with a velocity `1//1000^(th)` of the velocity of light in a magnetic field of induction `2/sqrt(3) xx 10^(-5) Wb//m^(2)` and perpendicular to the field then q is

A

5000 C

B

5000 `mu` C

C

500 `mu`C

D

500 C

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    TARGET PUBLICATION|Exercise Critical Thinking Introduction|41 Videos
  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    TARGET PUBLICATION|Exercise Competitive Thinking Introduction|61 Videos
  • LAWS OF MOTION

    TARGET PUBLICATION|Exercise EXERCISE|281 Videos
  • MAGNETISM

    TARGET PUBLICATION|Exercise MCQs|147 Videos

Similar Questions

Explore conceptually related problems

A force of 1.732 xx 10^-2 N acts on a particle of charge moving with a velocity 1/(1000^th) of the velocity of light in a magnetic field 2sqrt3xx 10^-5T and perpendicular to the field then q is

The force acting on a particle of charge q moving in a uniform magnets field with velocity v is

If a particle of charge q is moving with a velocity v in a direction opposite to the magnetic field B, then the force acting on the particle is.

A conductor of length 0.3 m moves with a uniform velocity of 10 m//s at right angles to the magnetic field of induction 0.5 xx 10^-4 Wb//m^2 . Calculate the e.m.f. induced in it.

A copper rod 1.5m long is rotated in a magnetic field of induction 6 xx 10^-5 (Wb)/m^2 .If it performs 1200 r.p.m.. find the e.m.f induced at its ends.

When a particle carrying a charge of 200 mu C moves at an angle 30^(@) to a uniform magnetic field of induction 5 xx 10^(-5) Wb//m^(2) with a speed of 2 xx 10^(5) m//s . The force acting on the particle is

The conductor moving with uniform velocity of 10 m//s at right angles to the magnetic field of induction 0.4 xx 10^-4 Wb//m^2 . Calculate length of the conductor if the e.m.f. induced at the ends of conductor is 6 xx 10^-5V .

A straight conductor is moving with a velocity of 18 km//hr at right angles to magnetic field at induction 3.6 xx 10^-5T . Find length at conductor if e.m.f. developed at its end is 45xx10^-5V .

What is the direction of the force acting on a charged particle q, moving with velocity vec v in a uniform magnetic field?

A straight conductor of length 0.4 m is moving with a velocity of 7m//s , in a magnetic field of induction 2 Wb//m^2 . The value of the maximum induced e.m.f. in the conductor is