Home
Class 11
PHYSICS
A magnetic needle lying parallel to a ma...

A magnetic needle lying parallel to a magnetic field requires `W units` of work to turn it through `60^(@)`. The torque needed to maintain the needle in this position will be

A

`sqrt(3)m`

B

W

C

0

D

`(sqrt(3)//2)` W

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    TARGET PUBLICATION|Exercise Competitive Thinking Introduction|61 Videos

  • LAWS OF MOTION

    TARGET PUBLICATION|Exercise EXERCISE|281 Videos

  • MAGNETISM

    TARGET PUBLICATION|Exercise MCQs|147 Videos

Similar Questions

Explore conceptually related problems

A magnetic needle is kept in a non uniform magnetic field.It experiences

A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equilibrium state. The energy required to rotate it by 60^(@) is W. Now the torque required to keep the magnet in this new position is

A rectangular coil 20cmxx20cm has 100 turns and carries a current of 1 A . It is placed in a uniform magnetic field B=0.5 T with the direction of magnetic field parallel to the plane of the coil. The magnitude of the torque required to hold this coil in this position is

Choose the corect options. A magnetic needle kept non-parallel to the magnetic field in a non-uniform magnetic field experiences A. a force but not a torque B. a torque but not a force C. both a force and a torque D. neither force nor a torque

A bar magnet having a magnetic moment of 2 xx l0 ^4 JT^-1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 xx 10^-4 T exits in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60^@ from the field is:

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian, has its north tip pointing down at 21^@ 48^1 with the horizontal. If the horizontal component of the earth's magnetic induction at that place is 3.5 xx 10^-5 T, determine the earth's magnetic induction at that place.

Take the inside tray of a used up match box and place a small magnetic needle inside the tray . Now take a long connecting wire and wind it around the tray . Complete the electric circuit ny connecting in it , this wire , electric cell , plug key and a bulb as shown in the below figure .: Mark the position of the magnetic needle . take a bar magnet near to the magnetic needle . keep looking at the needle and close the plug key . the bulb will light up , and you will realize that the current has started flowing . does the magnetic needle change its position ? :

A magnetic needle is suspended freely so that it can rotate freely in the magnetic meridian. In order to keep it in the horizontal position, a weight of 0.2 g is kept on one end of the needle. If the pole strength of this needle is 20 Am, find the value of the vertical component of the earth s magnetic field, (g = 9.8 m//s^-2)

Take the inside tray of a used up match box and place a small magnetic needle inside the tray . Now take a long connecting wire and wind it around the tray . Complete the electric circuit ny connecting in it , this wire , electric cell , plug key and a bulb as shown in the below figure .: Mark the position of the magnetic needle . take a bar magnet near to the magnetic needle .: What do you observe ? :