Home
Class 11
PHYSICS
A particle of mass m and charge q is acc...

A particle of mass m and charge q is accelerated through a potential differece V to a velocity `vecv` towards south. The particle enters a region with both a magnetic field `vecB` (pointing eastwards) and electric field `vecE` (pointing downwards). The particle travels with a constant velocity through this region. The potential difference V through this region should be equal to

A

`mE^(2)//2qB^(2)`

B

`2mE//qB`

C

E/qB

D

`E^(2)//qB`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    TARGET PUBLICATION|Exercise Competitive Thinking Introduction|61 Videos

  • LAWS OF MOTION

    TARGET PUBLICATION|Exercise EXERCISE|281 Videos

  • MAGNETISM

    TARGET PUBLICATION|Exercise MCQs|147 Videos

Similar Questions

Explore conceptually related problems

An electron emitted by a heated cathode and accelerated through a potential difference of 2.0 kV, enters a region with uniform magnetic field of 0.15 T. Determine the trajectory of the electron if the field is transverse to its initial velocity .

An electron emitted by a heated cathode and accelerated through a potential difference of 2.0 kV, enters a region with uniform magnetic field of 0.15 T. Determine the trajectory of the electron if the field makes an angle of 30^@ with the initial velocity .

A proton when accelerated through a potential difference of V volt has a wavelength lamda associated with it. An alpha-particle in order to have the same lamda must be accelerated through a potential difference of

A particle of mass 'm' and charge 'q' is incident on XZ plane with velocity 'v' in a direction making angle theta with a uniform magnetic field applied along X-axis. The magnetic field applied along X-axis. The nature of motion performed by the particle is

If a particle of charge q is moving with a velocity v in a direction opposite to the magnetic field B, then the force acting on the particle is.

A charged particle is in motion having initial velocity barV when it enter into a region of uniform magnetic field perpendicular to V. Because of the magnetic force the kinetic energy of the particle wil

What is the direction of the force acting on a charged particle q, moving with velocity vec v in a uniform magnetic field?

A particle of charge -32 xx 10^(-18) coulomb moving with velocity 20 ms^(-1) along the x-axis enters a region where a magnetic field of induction B is along the y-axis, and an electric field of magnitude 5 xx 10^(4) V/m is along the negative z-axis. If the charged particle continues moving along the x-axis, the magnitude of B is

A charged particle travels with a velocity barv through uniform magnetic field B as shown in the following figures. What is the direction of the magnetic force f_m due to magnetic field on the particle?