Home
Class 12
PHYSICS
A body moves along circular path of radi...

A body moves along circular path of radius 50 m and the coefficient of friction is 0.4. What should be its angular velocity is `rad//s` if it is not to slip from the surface? (g=9.8`m//s^2`)

A

2.8

B

0.28

C

0.27

D

2.7

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A car of mass 800 kg moves on a circular track of radius 40 m. If the coefficient of friction is 0.5, then maximum velocity with which the car can move is

A particle is moving along a circular path of radius 'r' with uniform angular velocity omega . Its angular acceleration is

A disc of mass 16 kg and radius 25 cm is rotated about its axis. What torque will increase its angular velocity from 0 to 8pi rad/s in 8 s ?

A body moving along a circular path of radius r with velocity V, has centripetal acceleration 'a'. If its velocity is made equal to 2V, then its centripetal acceleration is.

A body is whirled in a horizontal circle of radius 20cm . It has an angular velocity of 10rad//s . What is its linear velocity at any point on the circular path

Answer the following questions : What is the acceleration due to gravity at a height h (=radius of the earth) from the surface of the earth ? (g=9.8m/s^2)

A particle moves in a circular path of radius 0.4 m with a constan speed . If it makes 5 revolution in each second of its motion , then the speed of the particle will be

If a body of mass 5 kg is moving along a circle of radius lm with an angular velocity 2 rad/s, then the centripetal force will be

A body of mass10 kg ismoving in a circle of radius 1 m with an angular velocity of 2 rad/s. The centripetal force is

A block of mass m=5kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2 . When a force F=40N is applied, the acceleration of the block will be (g=10m//s^(2)) .