Home
Class 12
PHYSICS
The angle turned by a body undergoing ci...

The angle turned by a body undergoing circular motion depends on time as `theta = theta_(0)+theta_(1)t+theta_(2)t^(2)`. Then the angular acceleration of the body is

A

`theta_1`

B

`theta_2`

C

`2theta_1`

D

`2theta_2`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

If tantheta=t then tan2theta+sec2theta=

If 2tan^(2)theta=sec^(2)theta , then the general solution of theta -

If tan theta+tan 2theta+tan 3theta = tantheta tan 2theta tan 3theta then the general value of theta is

Angular displacement ( theta ) of a flywheel varies with time as theta=2t+3t^2 radian. The angular acceleration at t=2s is given by

The angular displacement of a particle performing circular motion is theta = (t^3)/60 - t/4 where theta is in radian and 't' is in seconds. Then the acceleration of the particle at the end 10 s will be

If sec theta - tan theta = 1/2, then theta lies in the

If (1-tan^2theta)/(sec^2theta)=1/2 then the general value of theta is

The angular displacement of a particle performing circular motion is theta = (t^3)/60 - t/4 where theta is in radian and 't' is in seconds. Then the angular velocity and angular accleration of the particle at the end of 5 s will be