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Given radius of Earth 'R' and length of ...

Given radius of Earth 'R' and length of a day 'T' the height of a geostationary satellite is [G- Gravitational Constant, M-Mass of earth]

A

`((4pi^2GM)/(T^2))^(1//3)`

B

`((4piGM)/(R^2))^(1//3)-R`

C

`((GMT^2)/(4pi^2))^(1//3)-R`

D

`((GMT^2)/(4pi^2))^(1//3)+R`

Text Solution

Verified by Experts

The correct Answer is:
C
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