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A particle is executing a simple harmoni...

A particle is executing a simple harmonic motion. Its maximum acceleration is `alpha` and maximum velocity is `beta`. Then, its time period of vibration will be

A

`(2pibeta)/(prop)`

B

`(beta^2)/(prop^2)`

C

`prop/beta

D

`(beta^2)/prop`

Text Solution

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The correct Answer is:
A
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