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A particle executes linear simple harmon...

A particle executes linear simple harmonic motion with an amplitude of `3 cm`. When the particle is at `2 cm` from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is

A

`sqrt5/pi`

B

`sqrt5/(2pi)`

C

`(4pi)/sqrt5`

D

`(2pi)/sqrt3`

Text Solution

Verified by Experts

The correct Answer is:
C
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