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A simple pendulum with a bob of mass 'm'...

A simple pendulum with a bob of mass 'm' oscillates from A to C and back to A such that PB is H. If the acceleration due to gravity is 'g' , then the velocity of the bob, as it passes through B, is

A

mgH

B

`sqrt(2gH)`

C

2gH

D

zero

Text Solution

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The correct Answer is:
B
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