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A wire of length L is hanging from a fix...

A wire of length L is hanging from a fixed support. The length changes to `L_(1) and L_(2)` when masses `M_(1)and M_(2)` are suspended respectively from its free end. Then L is equal to

A

`(L_(1)+L_(2))/(2)`

B

`sqrt(L_(1)L_(2))`

C

`(L_(1)M_(2)+L_(2)M_(1))/(M_(1)+M_(2))`

D

`(L_(1)M_(2)-L_(2)M_(1))/(M_(2)-M_(1))`

Text Solution

Verified by Experts

The correct Answer is:
D
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