Home
Class 12
PHYSICS
The surface tension of two liquids are 3...

The surface tension of two liquids are 30 and 60 dyne `cm^(-1)` respectively. The liquid drop form at the ends of two tube of the same radius. The ratio of the weight of the two drops is

A

`1:2`

B

`1:3`

C

`2:3`

D

`3:4`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The surface tension of a liquid is 10^(8) dyne cm^(-1) . It is equivalent to

The total energy of the free surface of a liquid drop is 2 pi times the surface tension of the liquid. What is the diameter of the drop ?

When a capillary tube of radius 'r' is dipped vertically in a liquid of surface tension T, the liquid rises to a height 'h' in the tube above the level outside the tube. If the angle of contact is theta , the density of the liquid is rho , then the pressure difference is.

A liquid drop having surface energy E is spread into 512 droplets of same size. The final surface energy of the droplets is

Two arcs of the same length subtend angles of 60^@ and 75^@ at the centres of the circles.What is the ratio of the radii of the two circles?

The surface tension of a liquid is 5Nm^-1 . If a thin film formed on a loop of area 0.02m^-2 then its surface energy will be

Let T_1 be surface tension between solid and air , T_2 be the surface tension between solid and liquid and T be the surface tension between liquid and air . Then in equilibrium, for a drop of liquid on a clean glass plate. The relation is ( theta is angle of contact )

The surface tension of water is 7xx10^(-2) N/m . The work required to break a drop of water of radius 0.5 cm into identical drops , each of radius 1 mm is

The surface tension of water is 0.07 N/m . Find the weight of water supported by surface tension in a capillary tube with a radius of 0.1 mm.

The excess pressure in dyne/ cm^2 inside a liquid drop of radius 2 mm and surface tension T dyne/ cm is