Home
Class 12
PHYSICS
Assertion : if work done in increasing ...

Assertion : if work done in increasing th size of a soap film from 10 cm `xx` 4 cm to `10cm xx8cm `is `2xx10^(-4)`J, then the surface tension is `5xx10^(-4)N m^(-1)`
Reason : work done = surface tension `xx` increase in area .

A

Assertion is true ,Reason is true , ,Reason is a correct explanation for Assertion

B

Assertion is True , reason Is True reason is not a correct explanation for asserion

C

Assertion is True , Reason is False

D

Assertion is false but reason is true

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The work done in increasing the size of a soap film from 10 cm × 6 cm to 10 cm × 11 cm is 3 xx10^(-4) joule . The surface tension of the film is

Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. (surface tension of soap solution = 0.3 Nm^(-1))

Calculate the work done in increasing the radius of a soap bubble in air from 2 cm to 3 cm. The surface tension of soap solution is 25 dyne/cm.

The work done in forming a soap film of size 10 cm xx10 cm will be if the surface tension of soap solution is 3xx10^-2 N//m :

Calculate the work done in increasing the radius of a soap bubble in air from 1 cm to 2 cm. The surface tension of soap solution is 30 dyne/cm . (pi = 3.142)

The surface tension of a liquid is 10^(8) dyne cm^(-1) . It is equivalent to

A rectangular film of liquid is extended from (4 cm xx 2 cm) to (5 cm xx 4 xx cm) . If the work done is 3 xx 10^(-4)J , the value of the surface tension of the liquid is

The work done in blowing a soap bubble from a radius of 6 cm to 9 cm if surface tension of soap solution is 25xx10^(-3) N//m , is

The surface tension of soap solution is 2.1xx10^-2 N//m . Then the work done in blowing a soap bubble of diameter 3.0 cm is

The surface tension of a soap solution is 2.1xx10^(-2) N//m . The work done in blowing a soap bubble of diameter 6.0 cm is