Let T1 be surface tension between solid ...

Let `T_1` be surface tension between solid and air , `T_2` be the surface tension between solid and liquid and T be the surface tension between liquid and air . Then in equilibrium, for a drop of liquid on a clean glass plate. The relation is (`theta` is angle of contact )

A

`cos theta=(T)/(T_1+T_2)`

B

`cos theta=(T)/(T_1-T_2)`

C

`cos theta=(T_1+T_2)/(T)`

D

`cos theta=(T_1-T_2)/(T)`

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The correct Answer is:

D

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