Home
Class 12
PHYSICS
The path difference between the two wave...

The path difference between the two waves
`y_(1)=a_(1) sin(omega t-(2pi x)/(lambda)) and y(2)=a_(2) cos(omega t-(2pi x)/(lambda)+phi)` is

A

` (lambda )/( 2pi )phi `

B

` (lambda ) /( 2pi) (phi +(pi)/(2))`

C

` (2pi )/( lambda ) ( phi -(pi)/(2))`

D

` (2pi)/( lambda) phi`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

when two displacements represented by y_(1) = a sin(omega t) and y_(2) = b cos (omega t) are superimposed the motion is

Equation of motion in the same direction are given by ltbygt y_(1)=2a sin (omega t-kx) and y_(2)=2a sin (omega t-kx - theta ) The amplitude of the medium particle will be

Equations of two progressive waves at a certain point in a medium are given by, y_1 =a_1 sin ( omega t+phi _1) and y_ 1 =a_2 sin (omegat+ phi _2) If amplitude and time period of resultant wave formed by the superposition of these two waves is same as that of both the waves,then phi _ 1-phi _2 is

Two waves y_(1) =A_(1) sin (omega t - beta _(1)), y_(2)=A_(2) sin (omega t - beta_(2) Superimpose to form a resultant wave whose amplitude is

Find the amplitude of the resultant wave produced due to interference of two waves given as, y_1 =A_1 sin (omega)t y_2 = A_2 sin [ (omega)t + (phi) ]

The displacement of the interfaring light waves are y_1 =4 sin omega t and y_2=3sin (omegat +(pi)/( 2)) What is the amplitude of the resultant wave?

The amplitude of a wave represented by displacement equation y=(1)/(sqrt(a)) sin omega t +-(1)/(sqrt(b)) cos omega t will be

A point mass is subjected to two simultaneous sinusoidal displacement in x- direction, x_(1)(t) = A sin omegat and x_(2)(t) = A sin(omega + (2pi)/(3)) . Adding a third sinusoidal displacement x_(3)(t) = B sin (omegat + phi) brings the mass to complete rest. The value of B and phi are

Two simple harmonic motions are given by y_(1) = a sin [((pi)/(2))t + phi] and y_(2) = b sin [((2pi)/( 3))t + phi] . The phase difference between these after 1 s is