Home
Class 12
PHYSICS
A string is producing transverse vibrati...

A string is producing transverse vibration whose equation is y = 0.021 sin ( x + 30 t ) , where x and y are in metre and t is in second . If the linear density of the string is `1.3xx10^(-4)kg//m` , then tension in string in newton will be

A

10 N

B

0.5 N

C

1 N

D

0.117 N

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A progressive wave is represented by the equation y= 0.5 sin ( 314t- 12.56x) where y and x are in metre and t is in second .Its wavelength is

The wave described by y = 0.25 sin ( 10 pix -2pi t ) where x and y are in meters and t in seconds , is a wave travelling along the

A transverse progressive wave is given by the equation y = 2 cos (pi) (0.5x - 200 t) , where x and y are in cm and 't' in second. The true following statement is

The equation of a wave is given as y= 0.07 sin ( 12pi x -3000pi t ), where x is in metre and t is in x,then the correct value is

A wave is expressed by the equation y=0.5sinpi(0.01x-3t) where y and x are in metre and t in seconds. Find the speed of propagation.

The transverse displacement of a string fixed at both the ends is ,y=0.06sin(32πx​)cos(120πt) where x and y are in metres and t is in seconds. The length of the string is 1.5m and its mass is 3.0×10−2kg. The tension in the string is

The transverse displacement of a string clamped at its both ends is given by y(x, t) = 0.06 sin ((2pi)/3 x) cos(l20pit) where x and y are in m and t in s. The length of the string is 1.5 m and its mass is 3 xx 10^(-2) kg. The tension in the string is

A wave is represented by the equation y = A sin(10pix + 15pit + (pi)/(3)) where x is in meter and t is in seconds. The expression represents :

The equation of a transverse wave on a stretched string is , y = 2 sin 2 (pi) [ t / 0.04 - x / 40 ] where distances are in meter and time in second .Find the frequency

The equation of a transverse wave on a stretched string is , y = 2 sin 2 (pi) [ t / 0.04 - x / 40 ] where distances are in meter and time in second .Find the amplitude