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An open pipe is resonance is its 2^(nd) ...

An open pipe is resonance is its `2^(nd)` harmonic with tuning fork of freqency `f_(1)`. Now it is closed at one end. If the frequency of the tuning fork is increases slowly from `f_(1)`, then agaain a resonance is obtained with `a_(1)` frequency `f_(2)`. if in this case the pipe vibrates `n^(th)` harmonics, then

A

`n=3, f_(2)=(3)/(4)f_(1)`

B

`n=3, f_(2)=(5)/(4)f_(1)`

C

`n=5, f_(2)=(5)/(4)f_(1)`

D

`n=5, f_(2)=(3)/(4)f_(1)`

Text Solution

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The correct Answer is:
C
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